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I WAS FIGHTING 120 RANGERS INFO SAYS THEY DO 30-60DMG WITH A 60%CHANCE OF HITTING....
IN THE BATTLE THEY DID 4560 DMG..BY MY CALC'S THIER SHOULD ONLY DO (120*60)-40% = 4320 MAX ?(120*30)-40% = 2160 MIN
GOING BY THE OUTCOME THEY DID 38 EACH...IF 38 WAS ONLY 60% OF THIER DMG THEN 100% = 63 WHICH IS 3 MORE THEN THEY SUPPOSE TO DO?
ANY ONE CARE TO EXPLAIN THIS AS I AM CONFUSED......:confused:
its not 60% chance of hitting
its 60% chance of dealing max dmg which is 60dmg the rest of the army will deal min dmg=30
there are no units in this game that miss there atack the only unit that can deal 0dmg is Skunk
so if you want too count it would be about 5760dmg
72rangers (60%)X (max dmg) 60=4320 48rangers (40%) X (min dmg) 30=1440
since the dmg was only 4560 that means that less than 60% dealt max dmg
60% accuracy means 60% chance to hit with full damage (60) and 40% chance to hit with the lower damage (30).
Also, since the ranger does not have the "splash damage" ability, each ranger only attacks one of your units per round.
Thus, if the given damage of 60 exceeds what your unit has left in HP, the surplus will not carry over to any other units.
ah ok...so to calc battles the accuracy is the number of units doing max dmg and the rest doing min...thanks.
i read it as accuracy being hit chance i.e.if i had 60% accuracy in scoring a goal then i would get 6 goals in 10 tries ...meaning i miss 4....
i been doing my calc all time like this number of units times (((max+min)/2)-accuracy %) to get the dmg caused seems accuracy means a different thing in this game to real world meaning...lol
now i can start to do me calcs better :)